(x+3)^2-5=31

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Solution for (x+3)^2-5=31 equation: 



(x+3)^2-5=31

We move all terms to the left:

(x+3)^2-5-(31)=0

We add all the numbers together, and all the variables

(x+3)^2-36=0

We move all terms containing x to the left, all other terms to the right

(x+3)^2=36

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